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manthanein 发表于 2019-1-13 18:44:17

\(\D \frac{170-63k}{20}\)
\(\D \frac{200-63k}{20}\)

manthanein 发表于 2019-1-13 20:50:21

\(\D F(x)=mx+n\left\lceil{\D \frac{u-ax}{b}} \right\rceil\)
\(\D F(0)=n \left\lceil{\frac{u}{b}} \right\rceil\)

所以线段所在直线方程为\(\D y=m(x+k\frac{b}{a})+n \left\lceil{\frac{u}{b}} \right\rceil\)

manthanein 发表于 2019-1-13 20:58:04

\(\D y=mx+{\frac{n(u-ax)}{b}}\)
\(\D y=m(x+k\frac{b}{a})+n \left\lceil{\frac{u}{b}} \right\rceil\)
\(\D \frac{n(u-ax)}{b}=\frac{mkb}{a}+n \left\lceil{\frac{u}{b}} \right\rceil\)
\(\D an(u-ax)=mkb^2+abn \left\lceil{\frac{u}{b}} \right\rceil\)

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