平方数通解
整数边三角形ABC,∠C=120度,即$c^2=a^2+ab+b^2$,求$a,b,c$通解 c的前n项:7, 13, 14, 19, 21, 26, 28, 31, 35, 37, 38, 39, 42, 43, 52, 56, 57, 61, 62, 63, 65, 67, 70, 73, 74, 76, 77, 78, 79, 84, 86, 93, 95, 97, 103, 104, 105, 109, 111, 112, 114, 117, 119, 122, 124, 126, 127, 129, 130, 134, 139, 140, 143, 146, 148, 151, 152, 154, 155, 156, 157, 158, 161oeis 解释: Numbers with exactly one prime divisor of the form 6k+1 with multiplicity one. https://bbs.emath.ac.cn/thread-2281-1-1.html
https://bbs.emath.ac.cn/forum.php?mod=viewthread&tid=5665&extra=&highlight=a%5E2%2Bab%2Bb%5E2&page=1 原来我也曾参与过讨论的,今天咋没搜到老帖呢?
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