连续素数构成的素数

medie2005

上面的"运行到了第1000个素数""是说这个帖子的题目.

无心人

有这几个已经很乐观了啊

gxqcn

写了下代码：

1. // HugeCalcDemo.cpp : Defines the entry point for the console application.
2. //
4. // Project -> Setting -> C/C++ -> Code Generation --> Use run-time library:
5. // Win32 Debug: Debug Multithreaded DLL
6. // Win32 Release: Multithreaded DLL
8. #include <iostream.h>
10. #include "../../../HugeCalc_API/CppAPI/Include/HugeCalc.h" // 公共接口
11. #include "../../../HugeCalc_API/CppAPI/Include/HugeInt.h" // 10进制系统
12. #include "../../../HugeCalc_API/CppAPI/Include/HugeIntX.h" // 16进制系统
14. #pragma message( "automatic link to ../../../HugeCalc_API/CppAPI/Lib/HugeCalc.lib" )
15. #pragma comment( lib, "../../../HugeCalc_API/CppAPI/Lib/HugeCalc.lib" )
18. int main(int argc, char* argv[])
19. {
20. // printf("Hello World!\n");
22. cout << "Call " << HugeCalc::GetVer() << endl << endl;
24. if ( HC_LICENSE_NONE == HugeCalc::GetLicenseLevel())
25. {
26. cout << endl << "警告：您未通过 HugeCalc.dll 的许可认证！" \
27. << endl << endl << "解决方案可选下列方案之一：" \
28. << endl << " 一、请将本程序移动到“/CopyrightByGuoXianqiang/[../]”目录下运行；" \
29. << endl << " 二、或请在 HugeCalc.chm 中进行注册（一劳永逸）。" \
30. << endl << endl;
31. system( "pause" );
32. return (-1);
33. }
35. CHugeInt hugeNum;
37. UINT32 i, j, k = 1;
38. UINT32 u32LBound, u32UBound;
39. UINT32 u32BufferSize;
40. UINT32 *p, *lpPrimeBuffer;
42. // 初始化
43. HugeCalc::EnableTimer( TRUE );
44. HugeCalc::ResetTimer();
46. u32LBound = 1;
47. u32UBound = 10;
48. for ( i = 1; i < 8; ++i )
49. {
50. u32BufferSize = HugeCalc::GetPrimeCount( u32LBound, u32UBound );
51. lpPrimeBuffer = new UINT32[ u32BufferSize ];
53. HugeCalc::GetPrimeList( lpPrimeBuffer, u32BufferSize, u32LBound, u32UBound );
54. for ( j=0, p=lpPrimeBuffer; j<u32BufferSize; ++j, ++p )
55. {
56. hugeNum.DecLShift( i ) += *p;
58. if ( hugeNum.IsPrime() )
59. {
60. cout << endl << "No." << k + j << "\tPrime=" << *p
61. << "\tTotal Digits = " << hugeNum.GetDigits();
62. }
63. }
65. k += u32BufferSize;
66. delete []lpPrimeBuffer;
68. cout << endl << "已耗时：" << HugeCalc::GetTimerStr( FT_DOT06SEC_s ) << endl << endl;
70. u32LBound = u32UBound;
71. u32UBound *= 10;
72. }
74. system( "pause" );
76. return 0;
77. }

复制代码

无心人

这个题目有结果的 搜到了结果 不过看不太明白 你运行下 看和网上结果比较下 http://mathworld.wolfram.com/Smarandache-WellinNumber.html

gxqcn

老早就曾想到这个题目，感觉很有趣，但意义似乎不大， 没想到已专门给了这类数一个名称： 　　The $n$th Smarandache-Wellin number is the consecutive number sequence consisting of a concatenation of the digits of the first $n$ primes 我运行了一下程序，与 14# 所给链接数据一致。

无心人

那可以找更大的素数的