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发表于 2008-10-22 10:56:59
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显示全部楼层
-
- /*
- 作者： crazyd <crazydiamondzgy@hotmail.com>
- 日期： 2002-12-29
- 说明: 这段代码用嵌入式汇编写成,md5最为核心的部分用汇编写成
- 具有很高的运算速度,比C代码快将近两倍,
- 使用方法是按照次序调用MD5Init,MD5Update,MD5Final这三个函数
- 如下面的标准代码：
-
- 标准代码：
- #include "md5.h"
- void main()
- {
- MD5_CTX context;
-
- MD5Init (&context);
- MD5Update (&context, "crazyd", strlen("crazyd"));
- MD5Final (&context);
- }
-
- 特殊说明：
- context.state[0]是32位的无符号整数，后面的数组元素也是这样，
- 他们在内存的存放和显示的方向是相反的，所以要特别注意。
- */
- #include <windows.h>
-
- typedef struct {
- DWORD state[4]; //encypted message
- DWORD count[2]; //bits of plaintext
- unsigned char buffer[64];
- }MD5_CTX;
-
- void MD5Init(MD5_CTX *);
- void MD5Update(MD5_CTX *, unsigned char *, unsigned int);//待加密的明文是中间那个参数
- void MD5Final(MD5_CTX *);
-
- #define S11 7
- #define S12 12
- #define S13 17
- #define S14 22
- #define S21 5
- #define S22 9
- #define S23 14
- #define S24 20
- #define S31 4
- #define S32 11
- #define S33 16
- #define S34 23
- #define S41 6
- #define S42 10
- #define S43 15
- #define S44 21
-
- #define a esi
- #define b edi
- #define c edx
- #define d ebx
- #define tmp1 eax
- #define tmp2 ecx
-
- #define x(i) [x+4*i]
-
- static void MD5Transform (DWORD [4], unsigned char [64]);
-
- static unsigned char PADDING[64] = {
- 0x80, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
- 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
- 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0
- };
-
- #define FF(a, b, c, d, x, s, ac) \
- __asm mov tmp1,b \
- __asm and tmp1,c \
- __asm mov tmp2,b \
- __asm not tmp2 \
- __asm and tmp2,d \
- __asm or tmp2,tmp1 \
- __asm lea a,[tmp2+a+ac] \
- __asm add a,x \
- __asm rol a,s \
- __asm add a,b \
-
- #define GG(a, b, c, d, x, s, ac) \
- __asm mov tmp1,b \
- __asm and tmp1,d \
- __asm mov tmp2,d \
- __asm not tmp2 \
- __asm and tmp2,c \
- __asm or tmp2,tmp1 \
- __asm lea a,[tmp2+a+ac] \
- __asm add a,x \
- __asm rol a,s \
- __asm add a,b
-
- #define HH(a,b,c, d, x, s, ac) \
- __asm mov tmp2,b \
- __asm xor tmp2,c \
- __asm xor tmp2,d \
- __asm lea a,[tmp2+a+ac] \
- __asm add a,x \
- __asm rol a,s \
- __asm add a,b
-
- #define II(a, b, c, d, x, s, ac) \
- __asm mov tmp2,d \
- __asm not tmp2 \
- __asm or tmp2,b \
- __asm xor tmp2,c \
- __asm lea a,[tmp2+a+ac] \
- __asm add a,x \
- __asm rol a,s \
- __asm add a,b
-
- void MD5Init (MD5_CTX *context)
- {
- context->count[0] = context->count[1] = 0;
- context->state[0] = 0x67452301;
- context->state[1] = 0xefcdab89;
- context->state[2] = 0x98badcfe;
- context->state[3] = 0x10325476;
- }
-
- void MD5Update (MD5_CTX *context, unsigned char *input, unsigned int inputLen)
- {
- unsigned int i, index, partLen;
-
- index = (unsigned int)((context->count[0] >> 3) & 0x3F);
-
- if ((context->count[0] += ((DWORD)inputLen << 3)) < ((DWORD)inputLen << 3))
- context->count[1]++;
- context->count[1] += ((DWORD)inputLen >> 29);
-
- partLen = 64 - index;
-
- if (inputLen >= partLen) {
- CopyMemory(&context->buffer[index],input, partLen);
- MD5Transform (context->state, context->buffer);
-
- for (i = partLen; i + 63 < inputLen; i += 64){}
- index = 0;
- }
- else
- i = 0;
-
- /* Buffer remaining input */
- CopyMemory(&context->buffer[index],&input[i],inputLen-i);
- }
-
- void MD5Final (MD5_CTX *context)
- {
- unsigned char bits[8];
- unsigned int index, padLen;
-
- CopyMemory(bits,context->count,8);
-
- index = (unsigned int)((context->count[0] >> 3) & 0x3f);
- padLen = (index < 56) ? (56 - index) : (120 - index);
- MD5Update (context, PADDING, padLen);
- MD5Update (context, bits, 8);
- }
-
- static void MD5Transform (DWORD state[4], unsigned char block[64])
- {
- DWORD x[16];
- __asm {
- //initial
- mov a,0x67452301
- mov b,0xefcdab89
- mov c,0x98badcfe
- mov d,0x10325476
- //copy string from block to state
- //考虑到用API会影响寄存器，所以自己实现这一段内存拷贝
- push esi
- push edi
-
- xor ecx,ecx
- mov esi,dword ptr [block]
- lea edi,[x]
- ROLL:
- mov eax,dword ptr [esi+ecx]
- mov dword ptr [edi+ecx],eax
- add ecx,4
- cmp ecx,64
- jb ROLL
-
- pop edi
- pop esi
- }
-
- /* Round 1 */
- FF(a, b, c, d, x( 0), S11, 0xd76aa478); /* 1 */
- FF(d, a, b, c, x( 1), S12, 0xe8c7b756); /* 2 */
- FF(c, d, a, b, x( 2), S13, 0x242070db); /* 3 */
- FF(b, c, d, a, x( 3), S14, 0xc1bdceee); /* 4 */
- FF(a, b, c, d, x( 4), S11, 0xf57c0faf); /* 5 */
- FF(d, a, b, c, x( 5), S12, 0x4787c62a); /* 6 */
- FF(c, d, a, b, x( 6), S13, 0xa8304613); /* 7 */
- FF(b, c, d, a, x( 7), S14, 0xfd469501); /* 8 */
- FF(a, b, c, d, x( 8), S11, 0x698098d8); /* 9 */
- FF(d, a, b, c, x( 9), S12, 0x8b44f7af); /* 10 */
- FF(c, d, a, b, x(10), S13, 0xffff5bb1); /* 11 */
- FF(b, c, d, a, x(11), S14, 0x895cd7be); /* 12 */
- FF(a, b, c, d, x(12), S11, 0x6b901122); /* 13 */
- FF(d, a, b, c, x(13), S12, 0xfd987193); /* 14 */
- FF(c, d, a, b, x(14), S13, 0xa679438e); /* 15 */
- FF(b, c, d, a, x(15), S14, 0x49b40821); /* 16 */
-
- /* Round 2 */
- GG (a, b, c, d, x( 1), S21, 0xf61e2562); /* 17 */
- GG (d, a, b, c, x( 6), S22, 0xc040b340); /* 18 */
- GG (c, d, a, b, x(11), S23, 0x265e5a51); /* 19 */
- GG (b, c, d, a, x( 0), S24, 0xe9b6c7aa); /* 20 */
- GG (a, b, c, d, x( 5), S21, 0xd62f105d); /* 21 */
- GG (d, a, b, c, x(10), S22, 0x2441453); /* 22 */
- GG (c, d, a, b, x(15), S23, 0xd8a1e681); /* 23 */
- GG (b, c, d, a, x( 4), S24, 0xe7d3fbc8); /* 24 */
- GG (a, b, c, d, x( 9), S21, 0x21e1cde6); /* 25 */
- GG (d, a, b, c, x(14), S22, 0xc33707d6); /* 26 */
- GG (c, d, a, b, x( 3), S23, 0xf4d50d87); /* 27 */
- GG (b, c, d, a, x( 8), S24, 0x455a14ed); /* 28 */
- GG (a, b, c, d, x(13), S21, 0xa9e3e905); /* 29 */
- GG (d, a, b, c, x( 2), S22, 0xfcefa3f8); /* 30 */
- GG (c, d, a, b, x( 7), S23, 0x676f02d9); /* 31 */
- GG (b, c, d, a, x(12), S24, 0x8d2a4c8a); /* 32 */
-
- /* Round 3 */
- HH (a, b, c, d, x( 5), S31, 0xfffa3942); /* 33 */
- HH (d, a, b, c, x( 8), S32, 0x8771f681); /* 34 */
- HH (c, d, a, b, x(11), S33, 0x6d9d6122); /* 35 */
- HH (b, c, d, a, x(14), S34, 0xfde5380c); /* 36 */
- HH (a, b, c, d, x( 1), S31, 0xa4beea44); /* 37 */
- HH (d, a, b, c, x( 4), S32, 0x4bdecfa9); /* 38 */
- HH (c, d, a, b, x( 7), S33, 0xf6bb4b60); /* 39 */
- HH (b, c, d, a, x(10), S34, 0xbebfbc70); /* 40 */
- HH (a, b, c, d, x(13), S31, 0x289b7ec6); /* 41 */
- HH (d, a, b, c, x( 0), S32, 0xeaa127fa); /* 42 */
- HH (c, d, a, b, x( 3), S33, 0xd4ef3085); /* 43 */
- HH (b, c, d, a, x( 6), S34, 0x4881d05); /* 44 */
- HH (a, b, c, d, x( 9), S31, 0xd9d4d039); /* 45 */
- HH (d, a, b, c, x(12), S32, 0xe6db99e5); /* 46 */
- HH (c, d, a, b, x(15), S33, 0x1fa27cf8); /* 47 */
- HH (b, c, d, a, x( 2), S34, 0xc4ac5665); /* 48 */
-
- /* Round 4 */
- II (a, b, c, d, x( 0), S41, 0xf4292244); /* 49 */
- II (d, a, b, c, x( 7), S42, 0x432aff97); /* 50 */
- II (c, d, a, b, x(14), S43, 0xab9423a7); /* 51 */
- II (b, c, d, a, x( 5), S44, 0xfc93a039); /* 52 */
- II (a, b, c, d, x(12), S41, 0x655b59c3); /* 53 */
- II (d, a, b, c, x( 3), S42, 0x8f0ccc92); /* 54 */
- II (c, d, a, b, x(10), S43, 0xffeff47d); /* 55 */
- II (b, c, d, a, x( 1), S44, 0x85845dd1); /* 56 */
- II (a, b, c, d, x( 8), S41, 0x6fa87e4f); /* 57 */
- II (d, a, b, c, x(15), S42, 0xfe2ce6e0); /* 58 */
- II (c, d, a, b, x( 6), S43, 0xa3014314); /* 59 */
- II (b, c, d, a, x(13), S44, 0x4e0811a1); /* 60 */
- II (a, b, c, d, x( 4), S41, 0xf7537e82); /* 61 */
- II (d, a, b, c, x(11), S42, 0xbd3af235); /* 62 */
- II (c, d, a, b, x( 2), S43, 0x2ad7d2bb); /* 63 */
- II (b, c, d, a, x( 9), S44, 0xeb86d391); /* 64 */
-
- __asm {
- mov tmp1,DWORD PTR [state]
- add DWORD PTR [tmp1],a
- add DWORD PTR [tmp1+4],b
- add DWORD PTR [tmp1+8],c
- add DWORD PTR [tmp1+12],d
- }
- }
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发表于 2008-10-22 08:06:31
你怎么不考虑C/C++甚至汇编的MD5函数啊
1、应该有自映射的输入存在，但极少吧
2、我想，最少的次数都是很大的，或者说
MD5(x)如果在有限域F(2^128)中，按值组成
若干圆圈，则圈的数量是很少的
