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[求助] 求大家帮忙看看,这个方程如何解???如何用matlab求解?

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发表于 2016-4-18 16:49:47 | 显示全部楼层 |阅读模式
悬赏1金币未解决

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毋因群疑而阻独见  毋任己意而废人言
毋私小惠而伤大体  毋借公论以快私情
发表于 2016-4-18 19:56:25 | 显示全部楼层
{y[x] -> C[
      1] HypergeometricPFQ[{}, {2/3 - 13/(
        12 (-8 + 3 I Sqrt[237])^(1/3)) -
        1/12 (-8 + 3 I Sqrt[237])^(1/3),
       2/3 + 13/(24 (-8 + 3 I Sqrt[237])^(1/3)) + (13 I)/(
        8 Sqrt[3] (-8 + 3 I Sqrt[237])^(1/3)) +
        1/24 (-8 + 3 I Sqrt[237])^(1/3) - (
        I (-8 + 3 I Sqrt[237])^(1/3))/(8 Sqrt[3]),
       2/3 + 13/(24 (-8 + 3 I Sqrt[237])^(1/3)) - (13 I)/(
        8 Sqrt[3] (-8 + 3 I Sqrt[237])^(1/3)) +
        1/24 (-8 + 3 I Sqrt[237])^(1/3) + (
        I (-8 + 3 I Sqrt[237])^(1/3))/(8 Sqrt[3])}, (3 k x^4)/
      128] + (-3)^((
     13 + 4 (-8 + 3 I Sqrt[237])^(1/3) + (-8 + 3 I Sqrt[237])^(2/3))/(
     12 (-8 + 3 I Sqrt[237])^(1/3)))
      2^(-((7 (13 +
         4 (-8 + 3 I Sqrt[237])^(1/3) + (-8 + 3 I Sqrt[237])^(2/3)))/(
      12 (-8 + 3 I Sqrt[237])^(1/3)))) k^((
     13 + 4 (-8 + 3 I Sqrt[237])^(1/3) + (-8 + 3 I Sqrt[237])^(2/3))/(
     12 (-8 + 3 I Sqrt[237])^(1/3))) x^((
     13 + 4 (-8 + 3 I Sqrt[237])^(1/3) + (-8 + 3 I Sqrt[237])^(2/3))/(
     3 (-8 + 3 I Sqrt[237])^(1/3)))
      C[2] HypergeometricPFQ[{}, {4/3 + 13/(
        12 (-8 + 3 I Sqrt[237])^(1/3)) +
        1/12 (-8 + 3 I Sqrt[237])^(1/3),
       1 + 13/(8 (-8 + 3 I Sqrt[237])^(1/3)) + (13 I)/(
        8 Sqrt[3] (-8 + 3 I Sqrt[237])^(1/3)) +
        1/8 (-8 + 3 I Sqrt[237])^(1/3) - (
        I (-8 + 3 I Sqrt[237])^(1/3))/(8 Sqrt[3]),
       1 + 13/(8 (-8 + 3 I Sqrt[237])^(1/3)) - (13 I)/(
        8 Sqrt[3] (-8 + 3 I Sqrt[237])^(1/3)) +
        1/8 (-8 + 3 I Sqrt[237])^(1/3) + (
        I (-8 + 3 I Sqrt[237])^(1/3))/(8 Sqrt[3])}, (3 k x^4)/
      128] + (-3)^((-13 + 13 I Sqrt[3] +
      8 (-8 + 3 I Sqrt[237])^(1/3) - (-8 + 3 I Sqrt[237])^(2/3) -
      I Sqrt[3] (-8 + 3 I Sqrt[237])^(2/3))/(
     24 (-8 + 3 I Sqrt[237])^(1/3)))
      2^(-((7 (-13 + 13 I Sqrt[3] +
         8 (-8 + 3 I Sqrt[237])^(1/3) - (-8 + 3 I Sqrt[237])^(2/3) -
         I Sqrt[3] (-8 + 3 I Sqrt[237])^(2/3)))/(
      24 (-8 + 3 I Sqrt[237])^(1/3))))
      k^((-13 + 13 I Sqrt[3] +
      8 (-8 + 3 I Sqrt[237])^(1/3) - (-8 + 3 I Sqrt[237])^(2/3) -
      I Sqrt[3] (-8 + 3 I Sqrt[237])^(2/3))/(
     24 (-8 + 3 I Sqrt[237])^(1/3)))
      x^((-13 + 13 I Sqrt[3] +
      8 (-8 + 3 I Sqrt[237])^(1/3) - (-8 + 3 I Sqrt[237])^(2/3) -
      I Sqrt[3] (-8 + 3 I Sqrt[237])^(2/3))/(
     6 (-8 + 3 I Sqrt[237])^(1/3)))
      C[4] HypergeometricPFQ[{}, {1 - 13/(
        8 (-8 + 3 I Sqrt[237])^(1/3)) + (13 I)/(
        8 Sqrt[3] (-8 + 3 I Sqrt[237])^(1/3)) -
        1/8 (-8 + 3 I Sqrt[237])^(1/3) - (
        I (-8 + 3 I Sqrt[237])^(1/3))/(8 Sqrt[3]),
       4/3 - 13/(24 (-8 + 3 I Sqrt[237])^(1/3)) + (13 I)/(
        8 Sqrt[3] (-8 + 3 I Sqrt[237])^(1/3)) -
        1/24 (-8 + 3 I Sqrt[237])^(1/3) - (
        I (-8 + 3 I Sqrt[237])^(1/3))/(8 Sqrt[3]),
       1 + (13 I)/(4 Sqrt[3] (-8 + 3 I Sqrt[237])^(1/3)) - (
        I (-8 + 3 I Sqrt[237])^(1/3))/(4 Sqrt[3])}, (3 k x^4)/
      128] + (-3)^((-13 - 13 I Sqrt[3] +
      8 (-8 + 3 I Sqrt[237])^(1/3) - (-8 + 3 I Sqrt[237])^(2/3) +
      I Sqrt[3] (-8 + 3 I Sqrt[237])^(2/3))/(
     24 (-8 + 3 I Sqrt[237])^(1/3)))
      2^(-((7 (-13 - 13 I Sqrt[3] +
         8 (-8 + 3 I Sqrt[237])^(1/3) - (-8 + 3 I Sqrt[237])^(2/3) +
         I Sqrt[3] (-8 + 3 I Sqrt[237])^(2/3)))/(
      24 (-8 + 3 I Sqrt[237])^(1/3))))
      k^((-13 - 13 I Sqrt[3] +
      8 (-8 + 3 I Sqrt[237])^(1/3) - (-8 + 3 I Sqrt[237])^(2/3) +
      I Sqrt[3] (-8 + 3 I Sqrt[237])^(2/3))/(
     24 (-8 + 3 I Sqrt[237])^(1/3)))
      x^((-13 - 13 I Sqrt[3] +
      8 (-8 + 3 I Sqrt[237])^(1/3) - (-8 + 3 I Sqrt[237])^(2/3) +
      I Sqrt[3] (-8 + 3 I Sqrt[237])^(2/3))/(
     6 (-8 + 3 I Sqrt[237])^(1/3)))
      C[3] HypergeometricPFQ[{}, {1 - 13/(
        8 (-8 + 3 I Sqrt[237])^(1/3)) - (13 I)/(
        8 Sqrt[3] (-8 + 3 I Sqrt[237])^(1/3)) -
        1/8 (-8 + 3 I Sqrt[237])^(1/3) + (
        I (-8 + 3 I Sqrt[237])^(1/3))/(8 Sqrt[3]),
       4/3 - 13/(24 (-8 + 3 I Sqrt[237])^(1/3)) - (13 I)/(
        8 Sqrt[3] (-8 + 3 I Sqrt[237])^(1/3)) -
        1/24 (-8 + 3 I Sqrt[237])^(1/3) + (
        I (-8 + 3 I Sqrt[237])^(1/3))/(8 Sqrt[3]),
       1 - (13 I)/(4 Sqrt[3] (-8 + 3 I Sqrt[237])^(1/3)) + (
        I (-8 + 3 I Sqrt[237])^(1/3))/(4 Sqrt[3])}, (3 k x^4)/128]}}

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崩溃  发表于 2017-5-25 10:37
毋因群疑而阻独见  毋任己意而废人言
毋私小惠而伤大体  毋借公论以快私情
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发表于 2016-4-18 23:41:19 | 显示全部楼层
麻烦写清楚些,有些地方写乱了
毋因群疑而阻独见  毋任己意而废人言
毋私小惠而伤大体  毋借公论以快私情
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