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楼主 |
发表于 2024-6-12 08:51:51
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将n颗红珠子跟n颗黄珠子排成一行, 若它的任意一个连续片段中红珠子跟黄珠子最多相差3颗, 就称这种排法为好的排法。
得到这样一串数。谢谢 mathe!!!
{2, 6, 20, 62, 182, 516, 1430, 3902, 10532, 28206, 75110, 199172, 526502, 1388526, 3655460, 9610622, 25241942, 66246276, 173759030, 455555102, 1193954852,
3128406606, 8195459270, 21466359812, 56220397382, 147228386766, 385531871780, 1009501446302, 2643240902582, 6920758132356, 18120107236310, ......}
将n颗红珠子跟n颗黄珠子排成一行, 若它的任意一个连续片段中红珠子跟黄珠子最多相差4颗, 就称这种排法为好的排法。
得到这样一串数。谢谢 mathe!!!
{2, 6, 20, 70, 242, 816, 2690, 8710, 27812, 87846, 275090, 855520, 2645762, 8144646, 24976820, 76351750, 232776242, 708070416, 2149715330, 6515916550,
19722557252, 59625324006, 180074121170, 543359158720, 1638289712642, 4936369052166, 14865394662740, 44743546592710, 134616440085362, ......}
谢谢 mathe!!!目的很明确: 搞个“通吃公式”。类似彩珠手镯配色“通吃公式”。谢谢 mathe!!!
- Table[Total[EulerPhi[n/#] m^# & /[url=home.php?mod=space&uid=6175]@[/url] Divisors[n]/(2 n)] + (m^Ceiling[n/2] + m^Ceiling[(n + 1)/2])/4, {m, 2, 8}, {n, 30}]
复制代码
Table[Total[EulerPhi[n/#] m^# & /@ Divisors[n]/(2 n)] + (m^Ceiling[n/2] + m^Ceiling[(n + 1)/2])/4, {m, 2, 8}, {n, 30}]
2种颜色: {2, 3, 4, 6, 8, 13, 18, 30, 46, 78, 126, 224, 380, 687, 1224, 2250, 4112, 7685, 14310, 27012, 50964, 96909, 184410, 352698, 675188,
3种颜色: {3, 6, 10, 21, 39, 92, 198, 498, 1219, 3210, 8418, 22913, 62415, 173088, 481598, 1351983, 3808083, 10781954, 30615354, 87230157,
4种颜色: {4, 10, 20, 55, 136, 430, 1300, 4435, 15084, 53764, 192700, 704370, 2589304, 9608050, 35824240, 134301715, 505421344, 1909209550,
5种颜色: {5, 15, 35, 120, 377, 1505, 5895, 25395, 110085,493131,2227275,10196680,46989185,218102685,1017448143,4768969770,22440372245,
6种颜色: {6, 21, 56, 231, 888, 4291, 20646, 107331, 563786, 3037314, 16514106, 90782986, 502474356, 2799220041,15673673176, 88162676511,
7种颜色: {7, 28, 84, 406, 1855, 10528, 60028, 365260, 2250311, 14158228, 89937316, 576960734, 3726912175, 24223929112, 158254933900,
8种颜色: {8, 36, 120, 666, 3536, 23052, 151848,1058058,7472984,53762472,390582648,2863912668,21145502960,157077883188,1172820793824,
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