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发表于 2009-3-3 22:05:31
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显示全部楼层
我把我的运行结果附在了 108# 。
我搜索到的比你多 1105-1082=23 组,
可能与边界判定有关。比如我的前33组数据如下:- 00:00:00.000 No.1 exp( 2, 3, 7 ) = ( 0, 0, 0 )
- 00:00:00.000 No.2 exp( 2, 3, 7 ) = ( 1, 0, 0 )
- 00:00:00.000 No.3 exp( 2, 3, 7 ) = ( 2, 0, 0 )
- 00:00:00.000 No.4 exp( 2, 3, 7 ) = ( 3, 0, 0 )
- 00:00:00.000 No.5 exp( 2, 3, 7 ) = ( 4, 0, 0 )
- 00:00:00.000 No.6 exp( 2, 3, 7 ) = ( 5, 0, 0 )
- 00:00:00.000 No.7 exp( 2, 3, 7 ) = ( 6, 0, 0 )
- 00:00:00.000 No.8 exp( 2, 3, 7 ) = ( 7, 0, 0 )
- 00:00:00.000 No.9 exp( 2, 3, 7 ) = ( 13, 0, 0 )
- 00:00:00.000 No.10 exp( 2, 3, 7 ) = ( 14, 0, 0 )
- 00:00:00.000 No.11 exp( 2, 3, 7 ) = ( 15, 0, 0 )
- 00:00:00.000 No.12 exp( 2, 3, 7 ) = ( 18, 0, 0 )
- 00:00:00.000 No.13 exp( 2, 3, 7 ) = ( 24, 0, 0 )
- 00:00:00.000 No.14 exp( 2, 3, 7 ) = ( 27, 0, 0 )
- 00:00:00.000 No.15 exp( 2, 3, 7 ) = ( 31, 0, 0 )
- 00:00:00.000 No.16 exp( 2, 3, 7 ) = ( 32, 0, 0 )
- 00:00:00.000 No.17 exp( 2, 3, 7 ) = ( 34, 0, 0 )
- 00:00:00.000 No.18 exp( 2, 3, 7 ) = ( 36, 0, 0 )
- 00:00:00.000 No.19 exp( 2, 3, 7 ) = ( 0, 1, 0 )
- 00:00:00.000 No.20 exp( 2, 3, 7 ) = ( 1, 1, 0 )
- 00:00:00.000 No.21 exp( 2, 3, 7 ) = ( 2, 1, 0 )
- 00:00:00.000 No.22 exp( 2, 3, 7 ) = ( 3, 1, 0 )
- 00:00:00.000 No.23 exp( 2, 3, 7 ) = ( 4, 1, 0 )
- 00:00:00.000 No.24 exp( 2, 3, 7 ) = ( 5, 1, 0 )
- 00:00:00.000 No.25 exp( 2, 3, 7 ) = ( 6, 1, 0 )
- 00:00:00.000 No.26 exp( 2, 3, 7 ) = ( 7, 1, 0 )
- 00:00:00.000 No.27 exp( 2, 3, 7 ) = ( 8, 1, 0 )
- 00:00:00.000 No.28 exp( 2, 3, 7 ) = ( 11, 1, 0 )
- 00:00:00.000 No.29 exp( 2, 3, 7 ) = ( 12, 1, 0 )
- 00:00:00.000 No.30 exp( 2, 3, 7 ) = ( 17, 1, 0 )
- 00:00:00.000 No.31 exp( 2, 3, 7 ) = ( 18, 1, 0 )
- 00:00:00.000 No.32 exp( 2, 3, 7 ) = ( 39, 1, 0 )
- 00:00:00.000 No.33 exp( 2, 3, 7 ) = ( 73, 1, 0 )
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