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发表于 2025-1-31 07:07:59
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好题!!!更直观一点。1——100个圆时的100个解。 a = 15, b = 8, c = 17, 4个算式是相通的。
- Table[((1 - Power[(b + c - a)/(b + c + a), (n)^-1]) Sqrt[((b + c)^2 - a^2) (a^2 - (b - c)^2)])/(4 a), {a, 15, 15}, {b, 8, 8}, {c, 17, 17}, {n, 100}] // FullSimplify
- Table[((Power[b + c + a, (n)^-1] - Power[b + c - a, (n)^-1]) Sqrt[((b + c)^2 - a^2) (a^2 - (b - c)^2)])/(4 a Power[b + c + a, (n)^-1]), {a, 15, 15}, {b, 8, 8}, {c, 17, 17}, {n, 100}]
- Table[((Power[b + a, (n)^-1] - Power[b - a, (n)^-1]) Sqrt[(b^2 - a^2) (a^2 - c^2)])/(4 a Power[b + a, (n)^-1]), {a, 15, 15}, {b, 25, 25}, {c, 9, 9}, {n, 100}] // FullSimplify
- Table[((Power[a, (n)^-1] - Power[b, (n)^-1]) Sqrt[a b ((a - b)^2 - 4 c^2)])/(4 (a - b) Power[a, (n)^-1]), {a, 40, 40}, {b, 10, 10}, {c, 9, 9}, {n, 100}] // FullSimplify
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{{{{3, 2, 4 - 2 2^(1/3), 4 - 2 Sqrt[2], 4 - 2 2^(3/5), 4 - 2 2^(2/3), 4 - 2 2^(5/7), 4 - 2 2^(3/4), 4 - 2 2^(7/9), 4 - 2 2^(4/5), 说明——4 - 2 2^(4/5) = 4 - 2×2^(4/5),
4 - 2 2^(9/11), 4 - 2 2^(5/6), 4 - 2 2^(11/13), 4 - 2 2^(6/7), 4 - 2 2^(13/15), 4 - 2 2^(7/8), 4 - 2 2^(15/17), 4 - 2 2^(8/9), 4 - 2 2^(17/19), 4 - 2 2^(9/10),
4 - 2 2^(19/21), 4 - 2 2^(10/11), 4 - 2 2^(21/23), 4 - 2 2^(11/12), 4 - 2 2^(23/25), 4 - 2 2^(12/13), 4 - 2 2^(25/27), 4 - 2 2^(13/14), 4 - 2 2^(27/29), 4 - 2 2^(14/15),
4 - 2 2^(29/31), 4 - 2 2^(15/16), 4 - 2 2^(31/33), 4 - 2 2^(16/17), 4 - 2 2^(33/35), 4 - 2 2^(17/18), 4 - 2 2^(35/37), 4 - 2 2^(18/19), 4 - 2 2^(37/39), 4 - 2 2^(19/20),
4 - 2 2^(39/41), 4 - 2 2^(20/21), 4 - 2 2^(41/43), 4 - 2 2^(21/22), 4 - 2 2^(43/45), 4 - 2 2^(22/23), 4 - 2 2^(45/47), 4 - 2 2^(23/24), 4 - 2 2^(47/49), 4 - 2 2^(24/25),
4 - 2 2^(49/51), 4 - 2 2^(25/26), 4 - 2 2^(51/53), 4 - 2 2^(26/27), 4 - 2 2^(53/55), 4 - 2 2^(27/28), 4 - 2 2^(55/57), 4 - 2 2^(28/29), 4 - 2 2^(57/59), 4 - 2 2^(29/30),
4 - 2 2^(59/61), 4 - 2 2^(30/31), 4 - 2 2^(61/63), 4 - 2 2^(31/32), 4 - 2 2^(63/65), 4 - 2 2^(32/33), 4 - 2 2^(65/67), 4 - 2 2^(33/34), 4 - 2 2^(67/69), 4 - 2 2^(34/35),
4 - 2 2^(69/71), 4 - 2 2^(35/36), 4 - 2 2^(71/73), 4 - 2 2^(36/37), 4 - 2 2^(73/75), 4 - 2 2^(37/38), 4 - 2 2^(75/77), 4 - 2 2^(38/39), 4 - 2 2^(77/79), 4 - 2 2^(39/40),
4 - 2 2^(79/81), 4 - 2 2^(40/41), 4 - 2 2^(81/83), 4 - 2 2^(41/42), 4 - 2 2^(83/85), 4 - 2 2^(42/43), 4 - 2 2^(85/87), 4 - 2 2^(43/44), 4 - 2 2^(87/89), 4 - 2 2^(44/45),
4 - 2 2^(89/91), 4 - 2 2^(45/46), 4 - 2 2^(91/93), 4 - 2 2^(46/47), 4 - 2 2^(93/95), 4 - 2 2^(47/48), 4 - 2 2^(95/97), 4 - 2 2^(48/49), 4 - 2 2^(97/99), 4 - 2 2^(49/50)}}}} |
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