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楼主: 王守恩

[原创] 数字串的通项公式

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 楼主| 发表于 2023-12-23 10:47:59 | 显示全部楼层
A000178    这样不也挺好?        \(\D a(n)=\prod_{k=0}^{n}k!\)

{1, 1, 2, 12, 288, 34560, 24883200, 125411328000, 5056584744960000, 1834933472251084800000, 6658606584104736522240000000,
265790267296391946810949632000000000, 127313963299399416749559771247411200000000000, 792786697595796795607377086400871488552960000000000000,
69113789582492712943486800506462734562847413501952000000000000000, 90378331112371142262979521568630736335023247731599748366336000000000000000000,
1890966832292234727042877370627225068196418587883634153182519380410368000000000000000000000}
毋因群疑而阻独见  毋任己意而废人言
毋私小惠而伤大体  毋借公论以快私情
 楼主| 发表于 2023-12-24 18:23:54 | 显示全部楼层
northwolves 发表于 2023-12-12 16:44
第一次接触到这个问题是好多好多年前了,大概初中二年级吧。有位邻居小哥哥(曾参加过80年代希望杯数学竞赛 ...

   A226053     这通项公式可以调整吗?
1, 3, 24, 815, 2263886, 9073564639850, 176228569027146222763928594, 84205747605016031994416006285857418872429042805656089,
18266661981464368900241497883663389900558206941880190662422226631656613685596278758397778714969996297024565,
  1. Table[Solve[{Floor[-1/x] == x1, Floor[1/(x + x1^-1)] == x2, Floor[-1/(x + x1^-1 - x2^-1)] == x3, Floor[1/(x + x1^-1 - x2^-1 + x3^-1)] == x4,
  2. Floor[-1/(x + x1^-1 - x2^-1 + x3^-1 - x4^-1)] == x5,Floor[1/(x + x1^-1 - x2^-1 + x3^-1 - x4^-1 + x5^-1)] == x6, Floor[-1/(x + x1^-1 - x2^-1 + x3^-1 - x4^-1 + x5^-1 - x6^-1)] == x7,
  3. Floor[1/(x + x1^-1 - x2^-1 + x3^-1 - x4^-1 + x5^-1 - x6^-1 + x7^-1)] == x8, Floor[-1/(x + x1^-1 - x2^-1 + x3^-1 - x4^-1 + x5^-1 - x6^-1 + x7^-1 - x8^-1)] == x9,
  4. Floor[1/(x + x1^-1 - x2^-1 + x3^-1 - x4^-1 + x5^-1 - x6^-1 + x7^-1 - x8^-1 + x9^-1)] == x10}, {x1, x2, x3, x4, x5, x6, x7, x8, x9, x10}], {x, 1/Sqrt[2] - 1, 1/Sqrt[2] - 1}]
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毋因群疑而阻独见  毋任己意而废人言
毋私小惠而伤大体  毋借公论以快私情
 楼主| 发表于 2024-1-8 08:05:45 | 显示全部楼层
A081721---1, 3, 10, 55, 377, 4291, 60028, 1058058, 21552969, 500280022, 12969598086, 371514016094, 11649073935505, 396857785692525, 14596464294191704, 576460770691256356,

\(\D a(n)=\sum_{k=1}^{n}\frac{n^{GCD(n, k)}}{2n}+\frac{n^{\lceil n/2\rceil}+n^{\lceil(n+1)/2\rceil}}{4}\)

OEIS没有我们的好。还可以更好吗?谢谢!
毋因群疑而阻独见  毋任己意而废人言
毋私小惠而伤大体  毋借公论以快私情
 楼主| 发表于 2024-1-11 13:14:20 | 显示全部楼层
A004041        这样不也挺好!?\(\D a(n)=\sum_{k=1}^{n}\frac{(2n-1)!!}{2k-1}\)

1, 4, 23, 176, 1689, 19524, 264207, 4098240, 71697105, 1396704420, 29985521895, 703416314160, 17901641997225, 491250187505700, 14459713484342175, 454441401368236800, ......
毋因群疑而阻独见  毋任己意而废人言
毋私小惠而伤大体  毋借公论以快私情
 楼主| 发表于 2024-1-16 15:23:42 | 显示全部楼层
A001175        F周期数       
1, 3, 8, 6, 20, 24, 16, 12, 24, 60, 10, 24, 28, 48, 40, 24, 36, 24, 18, 60, 16, 30, 48, 24, 100, 84, 72, 48, 14, 120, 30, 48, 40, 36, 80, 24, 76, 18, 56, 60, 40, 48, 88, 30, 120,
48, 32, 24, 112, 300, 72, 84, 108, 72, 20, 48, 72, 42, 58, 120, 60, 30, 48, 96, 140, 120, 136, 36, 48, 240, 70, 24, 148, 228, 200, 18, 80, 168, 78, 120, 216, 120, 168, 48, 180,
  1. F周期数公式。Module[{nn = 1000, F}, F = Fibonacci[Range[nn]]; Table[Length[FindTransientRepeat[Mod[F, n], 2][[2]]], {n, 85}]]
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A106291        L周期数       
1, 3, 8, 6, 4, 24, 16, 12, 24, 12, 10, 24, 28, 48, 8, 24, 36, 24, 18, 12, 16, 30, 48, 24, 20, 84, 72, 48, 14, 24, 30, 48, 40, 36, 16, 24, 76, 18, 56, 12, 40, 48, 88, 30, 24,
48, 32, 24, 112, 60, 72, 84, 108, 72, 20, 48, 72, 42, 58, 24, 60, 30, 48, 96, 28, 120, 136, 36, 48, 48, 70, 24, 148, 228, 40, 18, 80, 168, 78, 24, 216, 120, 168, 48, 36,
  1. L周期数公式。n = 2; Table[p = i; a = Join[Table[-1, {n - 1}], {n}]; a = Mod[a, p]; b = a; k = 0; While[k++; a = RotateLeft[a]; a[[n]] = Mod[Plus @@ a, p]; b != a]; k, {i, 85}]
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  1. N周期数公式。n = 2; Table[p = i; a = Join[Table[-1, {n - 1}], {n}]; a = Mod[a, p]; b = a; k = 0; While[k++; a[[n]] = Mod[Plus @@ a, p]; a = RotateLeft[a]; b != a]; k, {i, 85}]
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1, 3, 8, 6, 20, 24, 16, 12, 24, 60, 10, 24, 28, 48, 40, 24, 36, 24, 18, 60, 16, 30, 48, 24, 100, 84, 72, 48, 14, 120, 30, 48, 40, 36, 80, 24, 76, 18, 56, 60, 40, 48, 88, 30, 120,
48, 32, 24, 112, 300, 72, 84, 108, 72, 20, 48, 72, 42, 58, 120, 60, 30, 48, 96, 140, 120, 136, 36, 48, 240, 70, 24, 148, 228, 200, 18, 80, 168, 78, 120, 216, 120, 168, 48, 180,
  1. V周期数公式。Table[a = {1, 1}; b = a; k = 0; While[k++; a = RotateLeft[a]; a[[2]] = Mod[Plus @@ a, n]; b != a]; k, {n, 2, 303}]
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  1. W周期数公式。Table[a = {1, 1}; b = a; k = 0; While[k++; a[[2]] = Mod[Plus @@ a, n]; a = RotateLeft[a]; b != a]; k, {n, 2, 303}]
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{3, 8, 6, 20, 24, 16, 12, 24, 60, 10, 24, 28, 48, 40, 24, 36, 24, 18, 60, 16, 30, 48, 24, 100, 84, 72, 48, 14, 120, 30, 48, 40, 36, 80, 24, 76, 18, 56, 60, 40, 48, 88, 30, 120,
48, 32, 24, 112, 300, 72, 84, 108, 72, 20, 48, 72, 42, 58, 120, 60, 30, 48, 96, 140, 120, 136, 36, 48, 240, 70, 24, 148, 228, 200, 18, 80, 168, 78, 120, 216, 120, 168, 48, 180,
说明。
1,n=150时, nn=1200, F周期数公式速度慢了。
2,N周期数公式=F周期数公式。一下子我还是找不到反例。各位网友!你能举出反例来吗?谢谢!
3,L周期数公式,N周期数公式。这两者怎么就变了?是怎么变的?这是关键。谢谢!
4,V周期数公式=W周期数公式=F周期数公式。
5,V周期数公式,W周期数公式。这两者怎么就变不出L周期数公式来了?。谢谢!
毋因群疑而阻独见  毋任己意而废人言
毋私小惠而伤大体  毋借公论以快私情
 楼主| 发表于 2024-1-27 10:45:10 | 显示全部楼层
  1. Table[Sum[ 2 (2 n)! (-1)^(k + 1)/(k (k + 2 n)), {k, \[Infinity]}], {n, 1, 19}]
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1,7,148,6396,468576,52148160,8203541760,1733641056000,473875121664000,162705528979660800,68557495081291776000,34783759238448439296000,
20917982343202389688320000,  14713230137865692249456640000,  11967468761587723030592225280000,  11146324252014844359615538790400000,
11785996694653187027881492375142400000,  14041737888806159459892732515844096000000,  18723173464036641306759645997849116672000000,
......
这串数还可以有其他通项吗?
毋因群疑而阻独见  毋任己意而废人言
毋私小惠而伤大体  毋借公论以快私情
 楼主| 发表于 2024-4-4 18:33:28 | 显示全部楼层
A240926      这个通项也可以。
               
4, 5, 9, 20, 49, 125, 324, 845, 2209, 5780, 15129, 39605, 103684, 271445, 710649, 1860500, 4870849, 12752045, 33385284, 87403805,
228826129, 599074580, 1568397609, 4106118245, 10749957124, 28143753125, 73681302249, 192900153620, 505019158609,  ......
  1. Table[4*Cosh[n*ArcCsch[2]]^2,{n,0,30}]//FullSimplify
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毋因群疑而阻独见  毋任己意而废人言
毋私小惠而伤大体  毋借公论以快私情
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